2(X2+2)-3=2x+1

Solution for 2(X2+2)-3=2x+1 equation:

2(X2+2)-3=2X+1

We move all terms to the left:

2(X2+2)-3-(2X+1)=0

We add all the numbers together, and all the variables

2(+X^2+2)-(2X+1)-3=0

We multiply parentheses

2X^2-(2X+1)+4-3=0

We get rid of parentheses

2X^2-2X-1+4-3=0

We add all the numbers together, and all the variables

2X^2-2X=0

a = 2; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·2·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*2}=\frac{0}{4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*2}=\frac{4}{4}
=1
$