2(a+1)+4(3a+5)=64

Solution for 2(a+1)+4(3a+5)=64 equation:

Simplifying
2(a + 1) + 4(3a + 5) = 64

Reorder the terms:
2(1 + a) + 4(3a + 5) = 64
(1 * 2 + a * 2) + 4(3a + 5) = 64
(2 + 2a) + 4(3a + 5) = 64

Reorder the terms:
2 + 2a + 4(5 + 3a) = 64
2 + 2a + (5 * 4 + 3a * 4) = 64
2 + 2a + (20 + 12a) = 64

Reorder the terms:
2 + 20 + 2a + 12a = 64

Combine like terms: 2 + 20 = 22
22 + 2a + 12a = 64

Combine like terms: 2a + 12a = 14a
22 + 14a = 64

Solving
22 + 14a = 64

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 14a = 64 + -22

Combine like terms: 22 + -22 = 0
0 + 14a = 64 + -22
14a = 64 + -22

Combine like terms: 64 + -22 = 42
14a = 42

Divide each side by '14'.
a = 3

Simplifying
a = 3