2(a+1)=5(a-(10-a))

Solution for 2(a+1)=5(a-(10-a)) equation:

Simplifying
2(a + 1) = 5(a + -1(10 + -1a))

Reorder the terms:
2(1 + a) = 5(a + -1(10 + -1a))
(1 * 2 + a * 2) = 5(a + -1(10 + -1a))
(2 + 2a) = 5(a + -1(10 + -1a))
2 + 2a = 5(a + (10 * -1 + -1a * -1))
2 + 2a = 5(a + (-10 + 1a))

Reorder the terms:
2 + 2a = 5(-10 + a + 1a)

Combine like terms: a + 1a = 2a
2 + 2a = 5(-10 + 2a)
2 + 2a = (-10 * 5 + 2a * 5)
2 + 2a = (-50 + 10a)

Solving
2 + 2a = -50 + 10a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-10a' to each side of the equation.
2 + 2a + -10a = -50 + 10a + -10a

Combine like terms: 2a + -10a = -8a
2 + -8a = -50 + 10a + -10a

Combine like terms: 10a + -10a = 0
2 + -8a = -50 + 0
2 + -8a = -50

Add '-2' to each side of the equation.
2 + -2 + -8a = -50 + -2

Combine like terms: 2 + -2 = 0
0 + -8a = -50 + -2
-8a = -50 + -2

Combine like terms: -50 + -2 = -52
-8a = -52

Divide each side by '-8'.
a = 6.5

Simplifying
a = 6.5