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2(a+3)-4=-(a-2)+33
We move all terms to the left:
2(a+3)-4-(-(a-2)+33)=0
We multiply parentheses
2a-(-(a-2)+33)+6-4=0
We calculate terms in parentheses: -(-(a-2)+33), so:We add all the numbers together, and all the variables
-(a-2)+33
We get rid of parentheses
-a+2+33
We add all the numbers together, and all the variables
-1a+35
Back to the equation:
-(-1a+35)
2a-(-1a+35)+2=0
We get rid of parentheses
2a+1a-35+2=0
We add all the numbers together, and all the variables
3a-33=0
We move all terms containing a to the left, all other terms to the right
3a=33
a=33/3
a=11
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