2(a+3)=10+4(a-8)

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Solution for 2(a+3)=10+4(a-8) equation: 



2(a+3)=10+4(a-8)

We move all terms to the left:

2(a+3)-(10+4(a-8))=0

We multiply parentheses

2a-(10+4(a-8))+6=0



We calculate terms in parentheses: -(10+4(a-8)), so:

10+4(a-8)

determiningTheFunctionDomain
4(a-8)+10

We multiply parentheses

4a-32+10

We add all the numbers together, and all the variables

4a-22

Back to the equation:

-(4a-22)



We get rid of parentheses

2a-4a+22+6=0

We add all the numbers together, and all the variables

-2a+28=0

We move all terms containing a to the left, all other terms to the right

-2a=-28

a=-28/-2

a=+14

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