2(a+3b+2c-6)=

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Solution for 2(a+3b+2c-6)= equation:


Simplifying
2(a + 3b + 2c + -6) = 0

Reorder the terms:
2(-6 + a + 3b + 2c) = 0
(-6 * 2 + a * 2 + 3b * 2 + 2c * 2) = 0
(-12 + 2a + 6b + 4c) = 0

Solving
-12 + 2a + 6b + 4c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 2a + 6b + 12 + 4c = 0 + 12

Reorder the terms:
-12 + 12 + 2a + 6b + 4c = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 2a + 6b + 4c = 0 + 12
2a + 6b + 4c = 0 + 12

Combine like terms: 0 + 12 = 12
2a + 6b + 4c = 12

Add '-6b' to each side of the equation.
2a + 6b + -6b + 4c = 12 + -6b

Combine like terms: 6b + -6b = 0
2a + 0 + 4c = 12 + -6b
2a + 4c = 12 + -6b

Add '-4c' to each side of the equation.
2a + 4c + -4c = 12 + -6b + -4c

Combine like terms: 4c + -4c = 0
2a + 0 = 12 + -6b + -4c
2a = 12 + -6b + -4c

Divide each side by '2'.
a = 6 + -3b + -2c

Simplifying
a = 6 + -3b + -2c

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