2(a+4)-7=1/2(5+2a)

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Solution for 2(a+4)-7=1/2(5+2a) equation:



2(a+4)-7=1/2(5+2a)
We move all terms to the left:
2(a+4)-7-(1/2(5+2a))=0
Domain of the equation: 2(5+2a))!=0
a∈R
We add all the numbers together, and all the variables
2(a+4)-(1/2(2a+5))-7=0
We multiply parentheses
2a-(1/2(2a+5))+8-7=0
We multiply all the terms by the denominator
2a*2(2a+5))-(1+8*2(2a+5))-7*2(2a+5))=0
We add all the numbers together, and all the variables
2a*2(2a+5))-(1+8*2(2a+5))-7*2(2a=0
Wy multiply elements
4a^2(2+32a^2(2=0

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