2(a+4)6a=48

Solution for 2(a+4)6a=48 equation:

2(a+4)6a=48

We move all terms to the left:

2(a+4)6a-(48)=0

We multiply parentheses

12a^2+48a-48=0

a = 12; b = 48; c = -48;
Δ = b2-4ac
Δ = 482-4·12·(-48)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48\sqrt{2}}{2*12}=\frac{-48-48\sqrt{2}}{24}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48\sqrt{2}}{2*12}=\frac{-48+48\sqrt{2}}{24}
$