2(a+4)=20+5(a-5)

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Solution for 2(a+4)=20+5(a-5) equation: 



2(a+4)=20+5(a-5)

We move all terms to the left:

2(a+4)-(20+5(a-5))=0

We multiply parentheses

2a-(20+5(a-5))+8=0



We calculate terms in parentheses: -(20+5(a-5)), so:

20+5(a-5)

determiningTheFunctionDomain
5(a-5)+20

We multiply parentheses

5a-25+20

We add all the numbers together, and all the variables

5a-5

Back to the equation:

-(5a-5)



We get rid of parentheses

2a-5a+5+8=0

We add all the numbers together, and all the variables

-3a+13=0

We move all terms containing a to the left, all other terms to the right

-3a=-13

a=-13/-3

a=4+1/3

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