2(a-4)+7(b-8)=

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Solution for 2(a-4)+7(b-8)= equation:


Simplifying
2(a + -4) + 7(b + -8) = 0

Reorder the terms:
2(-4 + a) + 7(b + -8) = 0
(-4 * 2 + a * 2) + 7(b + -8) = 0
(-8 + 2a) + 7(b + -8) = 0

Reorder the terms:
-8 + 2a + 7(-8 + b) = 0
-8 + 2a + (-8 * 7 + b * 7) = 0
-8 + 2a + (-56 + 7b) = 0

Reorder the terms:
-8 + -56 + 2a + 7b = 0

Combine like terms: -8 + -56 = -64
-64 + 2a + 7b = 0

Solving
-64 + 2a + 7b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '64' to each side of the equation.
-64 + 2a + 64 + 7b = 0 + 64

Reorder the terms:
-64 + 64 + 2a + 7b = 0 + 64

Combine like terms: -64 + 64 = 0
0 + 2a + 7b = 0 + 64
2a + 7b = 0 + 64

Combine like terms: 0 + 64 = 64
2a + 7b = 64

Add '-7b' to each side of the equation.
2a + 7b + -7b = 64 + -7b

Combine like terms: 7b + -7b = 0
2a + 0 = 64 + -7b
2a = 64 + -7b

Divide each side by '2'.
a = 32 + -3.5b

Simplifying
a = 32 + -3.5b

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