2(a-4)-3(a-2)=4(a+1)=4

Solution for 2(a-4)-3(a-2)=4(a+1)=4 equation:

2(a-4)-3(a-2)=4(a+1)=4

We move all terms to the left:

2(a-4)-3(a-2)-(4(a+1))=0

We multiply parentheses

2a-3a-(4(a+1))-8+6=0


We calculate terms in parentheses: -(4(a+1)), so:

4(a+1)

We multiply parentheses

4a+4

Back to the equation:

-(4a+4)


We add all the numbers together, and all the variables

-1a-(4a+4)-2=0

We get rid of parentheses

-1a-4a-4-2=0

We add all the numbers together, and all the variables

-5a-6=0

We move all terms containing a to the left, all other terms to the right

-5a=6

a=6/-5

a=-1+1/5