2(a-4)=3(a-5)

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Solution for 2(a-4)=3(a-5) equation: 



2(a-4)=3(a-5)

We move all terms to the left:

2(a-4)-(3(a-5))=0

We multiply parentheses

2a-(3(a-5))-8=0



We calculate terms in parentheses: -(3(a-5)), so:

3(a-5)

We multiply parentheses

3a-15

Back to the equation:

-(3a-15)



We get rid of parentheses

2a-3a+15-8=0

We add all the numbers together, and all the variables

-1a+7=0

We move all terms containing a to the left, all other terms to the right

-a=-7

a=-7/-1

a=+7

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