2(a-4)=4a-(10+4)=

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Solution for 2(a-4)=4a-(10+4)= equation: 



2(a-4)=4a-(10+4)=

We move all terms to the left:

2(a-4)-(4a-(10+4))=0

We add all the numbers together, and all the variables

2(a-4)-(4a-14)=0

We multiply parentheses

2a-(4a-14)-8=0

We get rid of parentheses

2a-4a+14-8=0

We add all the numbers together, and all the variables

-2a+6=0

We move all terms containing a to the left, all other terms to the right

-2a=-6

a=-6/-2

a=+3

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