2(a-4)=4a-(7a+8)

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Solution for 2(a-4)=4a-(7a+8) equation: 



2(a-4)=4a-(7a+8)

We move all terms to the left:

2(a-4)-(4a-(7a+8))=0

We multiply parentheses

2a-(4a-(7a+8))-8=0



We calculate terms in parentheses: -(4a-(7a+8)), so:

4a-(7a+8)

We get rid of parentheses

4a-7a-8

We add all the numbers together, and all the variables

-3a-8

Back to the equation:

-(-3a-8)



We get rid of parentheses

2a+3a+8-8=0

We add all the numbers together, and all the variables

5a=0

a=0/5

a=0

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