2(a-4b-6c)=n

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Solution for 2(a-4b-6c)=n equation:


Simplifying
2(a + -4b + -6c) = n
(a * 2 + -4b * 2 + -6c * 2) = n
(2a + -8b + -12c) = n

Solving
2a + -8b + -12c = n

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '8b' to each side of the equation.
2a + -8b + 8b + -12c = 8b + n

Combine like terms: -8b + 8b = 0
2a + 0 + -12c = 8b + n
2a + -12c = 8b + n

Add '12c' to each side of the equation.
2a + -12c + 12c = 8b + 12c + n

Combine like terms: -12c + 12c = 0
2a + 0 = 8b + 12c + n
2a = 8b + 12c + n

Divide each side by '2'.
a = 4b + 6c + 0.5n

Simplifying
a = 4b + 6c + 0.5n

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