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2(a-5)(a=+5)=21a
We move all terms to the left:
2(a-5)(a-(+5))=0
We add all the numbers together, and all the variables
2(a-5)(a-5)=0
We multiply parentheses ..
2(+a^2-5a-5a+25)=0
We multiply parentheses
2a^2-10a-10a+50=0
We add all the numbers together, and all the variables
2a^2-20a+50=0
a = 2; b = -20; c = +50;
Δ = b2-4ac
Δ = -202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{20}{4}=5$
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