2(a-5)+3(a-2)=8+7(a-4)

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Solution for 2(a-5)+3(a-2)=8+7(a-4) equation:



2(a-5)+3(a-2)=8+7(a-4)
We move all terms to the left:
2(a-5)+3(a-2)-(8+7(a-4))=0
We multiply parentheses
2a+3a-(8+7(a-4))-10-6=0
We calculate terms in parentheses: -(8+7(a-4)), so:
8+7(a-4)
determiningTheFunctionDomain 7(a-4)+8
We multiply parentheses
7a-28+8
We add all the numbers together, and all the variables
7a-20
Back to the equation:
-(7a-20)
We add all the numbers together, and all the variables
5a-(7a-20)-16=0
We get rid of parentheses
5a-7a+20-16=0
We add all the numbers together, and all the variables
-2a+4=0
We move all terms containing a to the left, all other terms to the right
-2a=-4
a=-4/-2
a=+2

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