2(a-5)=4a-(2a+10)

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Solution for 2(a-5)=4a-(2a+10) equation:


Simplifying
2(a + -5) = 4a + -1(2a + 10)

Reorder the terms:
2(-5 + a) = 4a + -1(2a + 10)
(-5 * 2 + a * 2) = 4a + -1(2a + 10)
(-10 + 2a) = 4a + -1(2a + 10)

Reorder the terms:
-10 + 2a = 4a + -1(10 + 2a)
-10 + 2a = 4a + (10 * -1 + 2a * -1)
-10 + 2a = 4a + (-10 + -2a)

Reorder the terms:
-10 + 2a = -10 + 4a + -2a

Combine like terms: 4a + -2a = 2a
-10 + 2a = -10 + 2a

Add '10' to each side of the equation.
-10 + 10 + 2a = -10 + 10 + 2a

Combine like terms: -10 + 10 = 0
0 + 2a = -10 + 10 + 2a
2a = -10 + 10 + 2a

Combine like terms: -10 + 10 = 0
2a = 0 + 2a
2a = 2a

Add '-2a' to each side of the equation.
2a + -2a = 2a + -2a

Combine like terms: 2a + -2a = 0
0 = 2a + -2a

Combine like terms: 2a + -2a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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