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2(a-6)=4a(2a-12)
We move all terms to the left:
2(a-6)-(4a(2a-12))=0
We multiply parentheses
2a-(4a(2a-12))-12=0
We calculate terms in parentheses: -(4a(2a-12)), so:We get rid of parentheses
4a(2a-12)
We multiply parentheses
8a^2-48a
Back to the equation:
-(8a^2-48a)
-8a^2+2a+48a-12=0
We add all the numbers together, and all the variables
-8a^2+50a-12=0
a = -8; b = 50; c = -12;
Δ = b2-4ac
Δ = 502-4·(-8)·(-12)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-46}{2*-8}=\frac{-96}{-16} =+6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+46}{2*-8}=\frac{-4}{-16} =1/4 $
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