2(ab+bc+ac)=s

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Solution for 2(ab+bc+ac)=s equation:


Simplifying
2(ab + bc + ac) = s

Reorder the terms:
2(ab + ac + bc) = s
(ab * 2 + ac * 2 + bc * 2) = s
(2ab + 2ac + 2bc) = s

Solving
2ab + 2ac + 2bc = s

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2bc' to each side of the equation.
2ab + 2ac + 2bc + -2bc = -2bc + s

Combine like terms: 2bc + -2bc = 0
2ab + 2ac + 0 = -2bc + s
2ab + 2ac = -2bc + s

Reorder the terms:
2ab + 2ac + 2bc + -1s = -2bc + 2bc + s + -1s

Combine like terms: -2bc + 2bc = 0
2ab + 2ac + 2bc + -1s = 0 + s + -1s
2ab + 2ac + 2bc + -1s = s + -1s

Combine like terms: s + -1s = 0
2ab + 2ac + 2bc + -1s = 0

The solution to this equation could not be determined.

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