2(b+1)+3=(b+2)

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Solution for 2(b+1)+3=(b+2) equation: 



2(b+1)+3=(b+2)

We move all terms to the left:

2(b+1)+3-((b+2))=0

We multiply parentheses

2b-((b+2))+2+3=0



We calculate terms in parentheses: -((b+2)), so:

(b+2)

We get rid of parentheses

b+2

Back to the equation:

-(b+2)



We add all the numbers together, and all the variables

2b-(b+2)+5=0

We get rid of parentheses

2b-b-2+5=0

We add all the numbers together, and all the variables

b+3=0

We move all terms containing b to the left, all other terms to the right

b=-3

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