2(b+1)+3=13-(b+2)

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Solution for 2(b+1)+3=13-(b+2) equation: 



2(b+1)+3=13-(b+2)

We move all terms to the left:

2(b+1)+3-(13-(b+2))=0

We multiply parentheses

2b-(13-(b+2))+2+3=0



We calculate terms in parentheses: -(13-(b+2)), so:

13-(b+2)

determiningTheFunctionDomain
-(b+2)+13

We get rid of parentheses

-b-2+13

We add all the numbers together, and all the variables

-1b+11

Back to the equation:

-(-1b+11)



We add all the numbers together, and all the variables

2b-(-1b+11)+5=0

We get rid of parentheses

2b+1b-11+5=0

We add all the numbers together, and all the variables

3b-6=0

We move all terms containing b to the left, all other terms to the right

3b=6

b=6/3

b=2

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