2(b+1)-(3+b)=5

Solution for 2(b+1)-(3+b)=5 equation:

Simplifying
2(b + 1) + -1(3 + b) = 5

Reorder the terms:
2(1 + b) + -1(3 + b) = 5
(1 * 2 + b * 2) + -1(3 + b) = 5
(2 + 2b) + -1(3 + b) = 5
2 + 2b + (3 * -1 + b * -1) = 5
2 + 2b + (-3 + -1b) = 5

Reorder the terms:
2 + -3 + 2b + -1b = 5

Combine like terms: 2 + -3 = -1
-1 + 2b + -1b = 5

Combine like terms: 2b + -1b = 1b
-1 + 1b = 5

Solving
-1 + 1b = 5

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1b = 5 + 1

Combine like terms: -1 + 1 = 0
0 + 1b = 5 + 1
1b = 5 + 1

Combine like terms: 5 + 1 = 6
1b = 6

Divide each side by '1'.
b = 6

Simplifying
b = 6