2(b+1)-(8+b)=-3

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Solution for 2(b+1)-(8+b)=-3 equation:


Simplifying
2(b + 1) + -1(8 + b) = -3

Reorder the terms:
2(1 + b) + -1(8 + b) = -3
(1 * 2 + b * 2) + -1(8 + b) = -3
(2 + 2b) + -1(8 + b) = -3
2 + 2b + (8 * -1 + b * -1) = -3
2 + 2b + (-8 + -1b) = -3

Reorder the terms:
2 + -8 + 2b + -1b = -3

Combine like terms: 2 + -8 = -6
-6 + 2b + -1b = -3

Combine like terms: 2b + -1b = 1b
-6 + 1b = -3

Solving
-6 + 1b = -3

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 1b = -3 + 6

Combine like terms: -6 + 6 = 0
0 + 1b = -3 + 6
1b = -3 + 6

Combine like terms: -3 + 6 = 3
1b = 3

Divide each side by '1'.
b = 3

Simplifying
b = 3

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