2(b+1)-36=3(3+26)

Solution for 2(b+1)-36=3(3+26) equation:

Simplifying
2(b + 1) + -36 = 3(3 + 26)

Reorder the terms:
2(1 + b) + -36 = 3(3 + 26)
(1 * 2 + b * 2) + -36 = 3(3 + 26)
(2 + 2b) + -36 = 3(3 + 26)

Reorder the terms:
2 + -36 + 2b = 3(3 + 26)

Combine like terms: 2 + -36 = -34
-34 + 2b = 3(3 + 26)

Combine like terms: 3 + 26 = 29
-34 + 2b = 3(29)

Multiply 3 * 29
-34 + 2b = 87

Solving
-34 + 2b = 87

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '34' to each side of the equation.
-34 + 34 + 2b = 87 + 34

Combine like terms: -34 + 34 = 0
0 + 2b = 87 + 34
2b = 87 + 34

Combine like terms: 87 + 34 = 121
2b = 121

Divide each side by '2'.
b = 60.5

Simplifying
b = 60.5