2(b+1)=4(b-2)

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Solution for 2(b+1)=4(b-2) equation: 


Simplifying
2(b + 1) = 4(b + -2)

Reorder the terms:
2(1 + b) = 4(b + -2)
(1 * 2 + b * 2) = 4(b + -2)
(2 + 2b) = 4(b + -2)

Reorder the terms:
2 + 2b = 4(-2 + b)
2 + 2b = (-2 * 4 + b * 4)
2 + 2b = (-8 + 4b)

Solving
2 + 2b = -8 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
2 + 2b + -4b = -8 + 4b + -4b

Combine like terms: 2b + -4b = -2b
2 + -2b = -8 + 4b + -4b

Combine like terms: 4b + -4b = 0
2 + -2b = -8 + 0
2 + -2b = -8

Add '-2' to each side of the equation.
2 + -2 + -2b = -8 + -2

Combine like terms: 2 + -2 = 0
0 + -2b = -8 + -2
-2b = -8 + -2

Combine like terms: -8 + -2 = -10
-2b = -10

Divide each side by '-2'.
b = 5

Simplifying
b = 5

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