2(b+1)=5(b-5)

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Solution for 2(b+1)=5(b-5) equation: 



2(b+1)=5(b-5)

We move all terms to the left:

2(b+1)-(5(b-5))=0

We multiply parentheses

2b-(5(b-5))+2=0



We calculate terms in parentheses: -(5(b-5)), so:

5(b-5)

We multiply parentheses

5b-25

Back to the equation:

-(5b-25)



We get rid of parentheses

2b-5b+25+2=0

We add all the numbers together, and all the variables

-3b+27=0

We move all terms containing b to the left, all other terms to the right

-3b=-27

b=-27/-3

b=+9

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