2(b+1)=6(b-2)

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Solution for 2(b+1)=6(b-2) equation: 



2(b+1)=6(b-2)

We move all terms to the left:

2(b+1)-(6(b-2))=0

We multiply parentheses

2b-(6(b-2))+2=0



We calculate terms in parentheses: -(6(b-2)), so:

6(b-2)

We multiply parentheses

6b-12

Back to the equation:

-(6b-12)



We get rid of parentheses

2b-6b+12+2=0

We add all the numbers together, and all the variables

-4b+14=0

We move all terms containing b to the left, all other terms to the right

-4b=-14

b=-14/-4

b=3+1/2

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