2(b+1)=8(2b-5)

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Solution for 2(b+1)=8(2b-5) equation:


Simplifying
2(b + 1) = 8(2b + -5)

Reorder the terms:
2(1 + b) = 8(2b + -5)
(1 * 2 + b * 2) = 8(2b + -5)
(2 + 2b) = 8(2b + -5)

Reorder the terms:
2 + 2b = 8(-5 + 2b)
2 + 2b = (-5 * 8 + 2b * 8)
2 + 2b = (-40 + 16b)

Solving
2 + 2b = -40 + 16b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-16b' to each side of the equation.
2 + 2b + -16b = -40 + 16b + -16b

Combine like terms: 2b + -16b = -14b
2 + -14b = -40 + 16b + -16b

Combine like terms: 16b + -16b = 0
2 + -14b = -40 + 0
2 + -14b = -40

Add '-2' to each side of the equation.
2 + -2 + -14b = -40 + -2

Combine like terms: 2 + -2 = 0
0 + -14b = -40 + -2
-14b = -40 + -2

Combine like terms: -40 + -2 = -42
-14b = -42

Divide each side by '-14'.
b = 3

Simplifying
b = 3

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