2(b+10)=58

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Solution for 2(b+10)=58 equation: 


Simplifying
2(b + 10) = 58

Reorder the terms:
2(10 + b) = 58
(10 * 2 + b * 2) = 58
(20 + 2b) = 58

Solving
20 + 2b = 58

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 2b = 58 + -20

Combine like terms: 20 + -20 = 0
0 + 2b = 58 + -20
2b = 58 + -20

Combine like terms: 58 + -20 = 38
2b = 38

Divide each side by '2'.
b = 19

Simplifying
b = 19

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