2(b+12)=162(b+12)=16

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Solution for 2(b+12)=162(b+12)=16 equation: 



2(b+12)=162(b+12)=16

We move all terms to the left:

2(b+12)-(162(b+12))=0

We multiply parentheses

2b-(162(b+12))+24=0



We calculate terms in parentheses: -(162(b+12)), so:

162(b+12)

We multiply parentheses

162b+1944

Back to the equation:

-(162b+1944)



We get rid of parentheses

2b-162b-1944+24=0

We add all the numbers together, and all the variables

-160b-1920=0

We move all terms containing b to the left, all other terms to the right

-160b=1920

b=1920/-160

b=-12

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