2(b+12)=162b+12=16

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Solution for 2(b+12)=162b+12=16 equation:



2(b+12)=162b+12=16
We move all terms to the left:
2(b+12)-(162b+12)=0
We multiply parentheses
2b-(162b+12)+24=0
We get rid of parentheses
2b-162b-12+24=0
We add all the numbers together, and all the variables
-160b+12=0
We move all terms containing b to the left, all other terms to the right
-160b=-12
b=-12/-160
b=3/40

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