2(b+12)=162b+12=16

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Solution for 2(b+12)=162b+12=16 equation: 



2(b+12)=162b+12=16

We move all terms to the left:

2(b+12)-(162b+12)=0

We multiply parentheses

2b-(162b+12)+24=0

We get rid of parentheses

2b-162b-12+24=0

We add all the numbers together, and all the variables

-160b+12=0

We move all terms containing b to the left, all other terms to the right

-160b=-12

b=-12/-160

b=3/40

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