2(b+12)=3b+24-b

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Solution for 2(b+12)=3b+24-b equation: 



2(b+12)=3b+24-b

We move all terms to the left:

2(b+12)-(3b+24-b)=0

We add all the numbers together, and all the variables

2(b+12)-(2b+24)=0

We multiply parentheses

2b-(2b+24)+24=0

We get rid of parentheses

2b-2b-24+24=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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