2(b+2)+(3b-8)=

Solution for 2(b+2)+(3b-8)= equation:

Simplifying
2(b + 2) + (3b + -8) = 0

Reorder the terms:
2(2 + b) + (3b + -8) = 0
(2 * 2 + b * 2) + (3b + -8) = 0
(4 + 2b) + (3b + -8) = 0

Reorder the terms:
4 + 2b + (-8 + 3b) = 0

Remove parenthesis around (-8 + 3b)
4 + 2b + -8 + 3b = 0

Reorder the terms:
4 + -8 + 2b + 3b = 0

Combine like terms: 4 + -8 = -4
-4 + 2b + 3b = 0

Combine like terms: 2b + 3b = 5b
-4 + 5b = 0

Solving
-4 + 5b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 5b = 0 + 4
5b = 0 + 4

Combine like terms: 0 + 4 = 4
5b = 4

Divide each side by '5'.
b = 0.8

Simplifying
b = 0.8