2(b+2)+b=2(6+b)+1

Solution for 2(b+2)+b=2(6+b)+1 equation:

Simplifying
2(b + 2) + b = 2(6 + b) + 1

Reorder the terms:
2(2 + b) + b = 2(6 + b) + 1
(2 * 2 + b * 2) + b = 2(6 + b) + 1
(4 + 2b) + b = 2(6 + b) + 1

Combine like terms: 2b + b = 3b
4 + 3b = 2(6 + b) + 1
4 + 3b = (6 * 2 + b * 2) + 1
4 + 3b = (12 + 2b) + 1

Reorder the terms:
4 + 3b = 12 + 1 + 2b

Combine like terms: 12 + 1 = 13
4 + 3b = 13 + 2b

Solving
4 + 3b = 13 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
4 + 3b + -2b = 13 + 2b + -2b

Combine like terms: 3b + -2b = 1b
4 + 1b = 13 + 2b + -2b

Combine like terms: 2b + -2b = 0
4 + 1b = 13 + 0
4 + 1b = 13

Add '-4' to each side of the equation.
4 + -4 + 1b = 13 + -4

Combine like terms: 4 + -4 = 0
0 + 1b = 13 + -4
1b = 13 + -4

Combine like terms: 13 + -4 = 9
1b = 9

Divide each side by '1'.
b = 9

Simplifying
b = 9