2(b+2)-(7b+8)=1

Solution for 2(b+2)-(7b+8)=1 equation:

Simplifying
2(b + 2) + -1(7b + 8) = 1

Reorder the terms:
2(2 + b) + -1(7b + 8) = 1
(2 * 2 + b * 2) + -1(7b + 8) = 1
(4 + 2b) + -1(7b + 8) = 1

Reorder the terms:
4 + 2b + -1(8 + 7b) = 1
4 + 2b + (8 * -1 + 7b * -1) = 1
4 + 2b + (-8 + -7b) = 1

Reorder the terms:
4 + -8 + 2b + -7b = 1

Combine like terms: 4 + -8 = -4
-4 + 2b + -7b = 1

Combine like terms: 2b + -7b = -5b
-4 + -5b = 1

Solving
-4 + -5b = 1

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -5b = 1 + 4

Combine like terms: -4 + 4 = 0
0 + -5b = 1 + 4
-5b = 1 + 4

Combine like terms: 1 + 4 = 5
-5b = 5

Divide each side by '-5'.
b = -1

Simplifying
b = -1