2(b+2)=3(b-2)

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Solution for 2(b+2)=3(b-2) equation: 



2(b+2)=3(b-2)

We move all terms to the left:

2(b+2)-(3(b-2))=0

We multiply parentheses

2b-(3(b-2))+4=0



We calculate terms in parentheses: -(3(b-2)), so:

3(b-2)

We multiply parentheses

3b-6

Back to the equation:

-(3b-6)



We get rid of parentheses

2b-3b+6+4=0

We add all the numbers together, and all the variables

-1b+10=0

We move all terms containing b to the left, all other terms to the right

-b=-10

b=-10/-1

b=+10

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