2(b+2)=3(b-3)

Solution for 2(b+2)=3(b-3) equation:

Simplifying
2(b + 2) = 3(b + -3)

Reorder the terms:
2(2 + b) = 3(b + -3)
(2 * 2 + b * 2) = 3(b + -3)
(4 + 2b) = 3(b + -3)

Reorder the terms:
4 + 2b = 3(-3 + b)
4 + 2b = (-3 * 3 + b * 3)
4 + 2b = (-9 + 3b)

Solving
4 + 2b = -9 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
4 + 2b + -3b = -9 + 3b + -3b

Combine like terms: 2b + -3b = -1b
4 + -1b = -9 + 3b + -3b

Combine like terms: 3b + -3b = 0
4 + -1b = -9 + 0
4 + -1b = -9

Add '-4' to each side of the equation.
4 + -4 + -1b = -9 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = -9 + -4
-1b = -9 + -4

Combine like terms: -9 + -4 = -13
-1b = -13

Divide each side by '-1'.
b = 13

Simplifying
b = 13