2(b+3)+b=2(b-1)-1

Solution for 2(b+3)+b=2(b-1)-1 equation:

2(b+3)+b=2(b-1)-1

We move all terms to the left:

2(b+3)+b-(2(b-1)-1)=0

We add all the numbers together, and all the variables

b+2(b+3)-(2(b-1)-1)=0

We multiply parentheses

b+2b-(2(b-1)-1)+6=0


We calculate terms in parentheses: -(2(b-1)-1), so:

2(b-1)-1

We multiply parentheses

2b-2-1

We add all the numbers together, and all the variables

2b-3

Back to the equation:

-(2b-3)


We add all the numbers together, and all the variables

3b-(2b-3)+6=0

We get rid of parentheses

3b-2b+3+6=0

We add all the numbers together, and all the variables

b+9=0

We move all terms containing b to the left, all other terms to the right

b=-9