2(b+3)+b=2(b-3)-1

Solution for 2(b+3)+b=2(b-3)-1 equation:

Simplifying
2(b + 3) + b = 2(b + -3) + -1

Reorder the terms:
2(3 + b) + b = 2(b + -3) + -1
(3 * 2 + b * 2) + b = 2(b + -3) + -1
(6 + 2b) + b = 2(b + -3) + -1

Combine like terms: 2b + b = 3b
6 + 3b = 2(b + -3) + -1

Reorder the terms:
6 + 3b = 2(-3 + b) + -1
6 + 3b = (-3 * 2 + b * 2) + -1
6 + 3b = (-6 + 2b) + -1

Reorder the terms:
6 + 3b = -6 + -1 + 2b

Combine like terms: -6 + -1 = -7
6 + 3b = -7 + 2b

Solving
6 + 3b = -7 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
6 + 3b + -2b = -7 + 2b + -2b

Combine like terms: 3b + -2b = 1b
6 + 1b = -7 + 2b + -2b

Combine like terms: 2b + -2b = 0
6 + 1b = -7 + 0
6 + 1b = -7

Add '-6' to each side of the equation.
6 + -6 + 1b = -7 + -6

Combine like terms: 6 + -6 = 0
0 + 1b = -7 + -6
1b = -7 + -6

Combine like terms: -7 + -6 = -13
1b = -13

Divide each side by '1'.
b = -13

Simplifying
b = -13