2(b+3)-(8-b)=-5

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Solution for 2(b+3)-(8-b)=-5 equation:



2(b+3)-(8-b)=-5
We move all terms to the left:
2(b+3)-(8-b)-(-5)=0
We add all the numbers together, and all the variables
2(b+3)-(-1b+8)-(-5)=0
We add all the numbers together, and all the variables
2(b+3)-(-1b+8)+5=0
We multiply parentheses
2b-(-1b+8)+6+5=0
We get rid of parentheses
2b+1b-8+6+5=0
We add all the numbers together, and all the variables
3b+3=0
We move all terms containing b to the left, all other terms to the right
3b=-3
b=-3/3
b=-1

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