2(b+3)=3(b-6)+12

Solution for 2(b+3)=3(b-6)+12 equation:

Simplifying
2(b + 3) = 3(b + -6) + 12

Reorder the terms:
2(3 + b) = 3(b + -6) + 12
(3 * 2 + b * 2) = 3(b + -6) + 12
(6 + 2b) = 3(b + -6) + 12

Reorder the terms:
6 + 2b = 3(-6 + b) + 12
6 + 2b = (-6 * 3 + b * 3) + 12
6 + 2b = (-18 + 3b) + 12

Reorder the terms:
6 + 2b = -18 + 12 + 3b

Combine like terms: -18 + 12 = -6
6 + 2b = -6 + 3b

Solving
6 + 2b = -6 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
6 + 2b + -3b = -6 + 3b + -3b

Combine like terms: 2b + -3b = -1b
6 + -1b = -6 + 3b + -3b

Combine like terms: 3b + -3b = 0
6 + -1b = -6 + 0
6 + -1b = -6

Add '-6' to each side of the equation.
6 + -6 + -1b = -6 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = -6 + -6
-1b = -6 + -6

Combine like terms: -6 + -6 = -12
-1b = -12

Divide each side by '-1'.
b = 12

Simplifying
b = 12