2(b+3)=57

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Solution for 2(b+3)=57 equation: 



2(b+3)=57

We move all terms to the left:

2(b+3)-(57)=0

We multiply parentheses

2b+6-57=0

We add all the numbers together, and all the variables

2b-51=0

We move all terms containing b to the left, all other terms to the right

2b=51

b=51/2

b=25+1/2

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