2(b+4)=-(3b+2)

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Solution for 2(b+4)=-(3b+2) equation: 



2(b+4)=-(3b+2)

We move all terms to the left:

2(b+4)-(-(3b+2))=0

We multiply parentheses

2b-(-(3b+2))+8=0



We calculate terms in parentheses: -(-(3b+2)), so:

-(3b+2)

We get rid of parentheses

-3b-2

Back to the equation:

-(-3b-2)



We get rid of parentheses

2b+3b+2+8=0

We add all the numbers together, and all the variables

5b+10=0

We move all terms containing b to the left, all other terms to the right

5b=-10

b=-10/5

b=-2

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