2(b+5)-3(b-3)=4

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Solution for 2(b+5)-3(b-3)=4 equation:


Simplifying
2(b + 5) + -3(b + -3) = 4

Reorder the terms:
2(5 + b) + -3(b + -3) = 4
(5 * 2 + b * 2) + -3(b + -3) = 4
(10 + 2b) + -3(b + -3) = 4

Reorder the terms:
10 + 2b + -3(-3 + b) = 4
10 + 2b + (-3 * -3 + b * -3) = 4
10 + 2b + (9 + -3b) = 4

Reorder the terms:
10 + 9 + 2b + -3b = 4

Combine like terms: 10 + 9 = 19
19 + 2b + -3b = 4

Combine like terms: 2b + -3b = -1b
19 + -1b = 4

Solving
19 + -1b = 4

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + -1b = 4 + -19

Combine like terms: 19 + -19 = 0
0 + -1b = 4 + -19
-1b = 4 + -19

Combine like terms: 4 + -19 = -15
-1b = -15

Divide each side by '-1'.
b = 15

Simplifying
b = 15

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