2(b+9)-7=3(b-1)

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Solution for 2(b+9)-7=3(b-1) equation: 



2(b+9)-7=3(b-1)

We move all terms to the left:

2(b+9)-7-(3(b-1))=0

We multiply parentheses

2b-(3(b-1))+18-7=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We add all the numbers together, and all the variables

2b-(3b-3)+11=0

We get rid of parentheses

2b-3b+3+11=0

We add all the numbers together, and all the variables

-1b+14=0

We move all terms containing b to the left, all other terms to the right

-b=-14

b=-14/-1

b=+14

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