2(b+c)+(b+c)+5b=

Solution for 2(b+c)+(b+c)+5b= equation:

Simplifying
2(b + c) + (b + c) + 5b = 0
(b * 2 + c * 2) + (b + c) + 5b = 0
(2b + 2c) + (b + c) + 5b = 0

Remove parenthesis around (b + c)
2b + 2c + b + c + 5b = 0

Reorder the terms:
2b + b + 5b + 2c + c = 0

Combine like terms: 2b + b = 3b
3b + 5b + 2c + c = 0

Combine like terms: 3b + 5b = 8b
8b + 2c + c = 0

Combine like terms: 2c + c = 3c
8b + 3c = 0

Solving
8b + 3c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3c' to each side of the equation.
8b + 3c + -3c = 0 + -3c

Combine like terms: 3c + -3c = 0
8b + 0 = 0 + -3c
8b = 0 + -3c
Remove the zero:
8b = -3c

Divide each side by '8'.
b = -0.375c

Simplifying
b = -0.375c