2(b+c)+3(b+c)+5b=

Solution for 2(b+c)+3(b+c)+5b= equation:

Simplifying
2(b + c) + 3(b + c) + 5b = 0
(b * 2 + c * 2) + 3(b + c) + 5b = 0
(2b + 2c) + 3(b + c) + 5b = 0
2b + 2c + (b * 3 + c * 3) + 5b = 0
2b + 2c + (3b + 3c) + 5b = 0

Reorder the terms:
2b + 3b + 5b + 2c + 3c = 0

Combine like terms: 2b + 3b = 5b
5b + 5b + 2c + 3c = 0

Combine like terms: 5b + 5b = 10b
10b + 2c + 3c = 0

Combine like terms: 2c + 3c = 5c
10b + 5c = 0

Solving
10b + 5c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5c' to each side of the equation.
10b + 5c + -5c = 0 + -5c

Combine like terms: 5c + -5c = 0
10b + 0 = 0 + -5c
10b = 0 + -5c
Remove the zero:
10b = -5c

Divide each side by '10'.
b = -0.5c

Simplifying
b = -0.5c