2(b-2)+6=210

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Solution for 2(b-2)+6=210 equation: 



2(b-2)+6=210

We move all terms to the left:

2(b-2)+6-(210)=0

We add all the numbers together, and all the variables

2(b-2)-204=0

We multiply parentheses

2b-4-204=0

We add all the numbers together, and all the variables

2b-208=0

We move all terms containing b to the left, all other terms to the right

2b=208

b=208/2

b=104

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