2(b-2)-10=2(b+3)

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Solution for 2(b-2)-10=2(b+3) equation:


Simplifying
2(b + -2) + -10 = 2(b + 3)

Reorder the terms:
2(-2 + b) + -10 = 2(b + 3)
(-2 * 2 + b * 2) + -10 = 2(b + 3)
(-4 + 2b) + -10 = 2(b + 3)

Reorder the terms:
-4 + -10 + 2b = 2(b + 3)

Combine like terms: -4 + -10 = -14
-14 + 2b = 2(b + 3)

Reorder the terms:
-14 + 2b = 2(3 + b)
-14 + 2b = (3 * 2 + b * 2)
-14 + 2b = (6 + 2b)

Add '-2b' to each side of the equation.
-14 + 2b + -2b = 6 + 2b + -2b

Combine like terms: 2b + -2b = 0
-14 + 0 = 6 + 2b + -2b
-14 = 6 + 2b + -2b

Combine like terms: 2b + -2b = 0
-14 = 6 + 0
-14 = 6

Solving
-14 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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